Given two strings s and goal, return true if and only if s can become goal after some number of shifts on s.
A shift on s consists of moving the leftmost character of s to the rightmost position.
- For example, if
s = "abcde", then it will be"bcdea"after one shift.
Example 1:
Input: s = "abcde", goal = "cdeab" Output: true
Example 2:
Input: s = "abcde", goal = "abced" Output: false
Constraints:
1 <= s.length, goal.length <= 100sandgoalconsist of lowercase English letters.
Companies:
Zoom, Apple, Goldman Sachs, LinkedIn
Related Topics:
String, String Matching
// OJ: https://leetcode.com/problems/rotate-string/
// Author: github.com/lzl124631x
// Time: O(N)
// Space: O(N)
class Solution {
public:
bool rotateString(string s, string goal) {
return goal.size() == s.size() && (s + s).find(goal) != string::npos;
}
};